What is the integral of tan^2(2/3)x ?

The integral of tan^2(2/3)x is (tan^2(2/3)x^2)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of tan^2(2/3)x

\int tan^{2} (\frac{2}{3}) x d x

\frac{tan ^{2} ( \frac{2}{3} ) x ^{2}}{2} + C

Solution steps

\int tan^{2} (\frac{2}{3}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= tan^{2} (\frac{2}{3}) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= tan^{2} (\frac{2}{3}) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{tan ^{2} ( \frac{2}{3} ) x ^{2}}{2}

Add a constant to the solution

= \frac{tan ^{2} ( \frac{2}{3} ) x ^{2}}{2} + C

\int - \frac{8}{x ^{3}} d x

\int 2 cos (x) - 3 sin (x) d x

\int cos (x y^{- \frac{1}{2}}) d x

\int 2 (2 x + 8)^{6} d x

\int x^{2} 4 - x^{3} d x

What is the integral of tan^2(2/3)x ?
The integral of tan^2(2/3)x is (tan^2(2/3)x^2)/2+C