What is the integral of cos(u)sin(u) ?

The integral of cos(u)sin(u) is (sin^2(u))/2+C

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integral of cos(u)sin(u)

\int cos (u) sin (u) d u

\frac{sin ^{2} ( u )}{2} + C

Solution steps

\int cos (u) sin (u) d u

Apply u-substitution

: \int v d v

= \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= \frac{v ^{2}}{2}

Substitute back

v = sin (u)

= \frac{sin ^{2} ( u )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( u )}{2} + C

\frac{\partial}{\partial y} (6 x y^{3})

\frac{d}{d x} (\frac{( x + 1 )}{x})

arcsin (4 x)

\int \frac{x ^{3}}{y ^{2}} d x

\frac{1}{( x + 1 ) ^{2}} 1

What is the integral of cos(u)sin(u) ?
The integral of cos(u)sin(u) is (sin^2(u))/2+C