What is the integral of 1/(\sqrt[4]{x^5)} ?

The integral of 1/(\sqrt[4]{x^5)} is -4/(\sqrt[4]{x)}+C

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integral of 1/(\sqrt[4]{x^5)}

Solution steps

Apply exponent rule:

(a^{n})^{m} = a^{n \cdot m}

= \int \frac{1}{x ^{\frac{5}{4}}} d x

Apply the Power Rule

Add a constant to the solution

\int (1 - \frac{1}{x}) cos (x - ln (x)) d x

\int \frac{1}{- x ^{2} - x + 2} d x

\int ln^{2} (y) d y

\int x^{4} x d x

\int x arcsin (4 x) d x

What is the integral of 1/(\sqrt[4]{x^5)} ?
The integral of 1/(\sqrt[4]{x^5)} is -4/(\sqrt[4]{x)}+C