What is the integral of ln^2(z) ?

The integral of ln^2(z) is zln^2(z)-2(zln(z)-z)+C

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integral of ln^2(z)

\int ln^{2} (z) d z

z ln^{2} (z) - 2 (z ln (z) - z) + C

Solution steps

\int ln^{2} (z) d z

Apply Integration By Parts

: z ln^{2} (z) - \int 2 ln (z) d z

= z ln^{2} (z) - \int 2 ln (z) d z

\int 2 ln (z) d z = 2 (z ln (z) - z)

= z ln^{2} (z) - 2 (z ln (z) - z)

Add a constant to the solution

= z ln^{2} (z) - 2 (z ln (z) - z) + C

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What is the integral of ln^2(z) ?
The integral of ln^2(z) is zln^2(z)-2(zln(z)-z)+C