What is the integral of 1 (sin(x)) ?

The integral of 1 (sin(x)) is -dcos(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1 (sin(x))

\int \frac{d}{1} (sin (x)) d x

- d cos (x) + C

Solution steps

\int \frac{d}{1} sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= d (- cos (x))

Simplify

= - d cos (x)

Add a constant to the solution

= - d cos (x) + C

\int 1 e^{- θ} cos (7 θ) d θ

\int \frac{9 x ^{3} - 6 x + 2}{x ^{3} - x ^{2}} d x

\int \frac{4 x}{100 + x ^{2}} d x

\int \frac{x ^{- 2}}{x ^{4}} d x

\int \frac{1}{4 x ^{2} + 4 x + 3} d x