What is the integral of (7x-14)/(x^2-3x-10) ?

The integral of (7x-14)/(x^2-3x-10) is 4ln|x+2|+3ln|x-5|+C

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integral of (7x-14)/(x^2-3x-10)

\int \frac{7 x - 14}{x ^{2} - 3 x - 10} d x

4 ln ∣ x + 2 ∣ + 3 ln ∣ x - 5 ∣ + C

Solution steps

\int \frac{7 x - 14}{x ^{2} - 3 x - 10} d x

Take the partial fraction of

\frac{7 x - 14}{x ^{2} - 3 x - 10} : \frac{4}{x + 2} + \frac{3}{x - 5}

= \int \frac{4}{x + 2} + \frac{3}{x - 5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{x + 2} d x + \int \frac{3}{x - 5} d x

\int \frac{4}{x + 2} d x = 4 ln ∣ x + 2 ∣

\int \frac{3}{x - 5} d x = 3 ln ∣ x - 5 ∣

= 4 ln ∣ x + 2 ∣ + 3 ln ∣ x - 5 ∣

Add a constant to the solution

= 4 ln ∣ x + 2 ∣ + 3 ln ∣ x - 5 ∣ + C

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What is the integral of (7x-14)/(x^2-3x-10) ?
The integral of (7x-14)/(x^2-3x-10) is 4ln|x+2|+3ln|x-5|+C