What is the integral of (sec^2(z))/(3+5tan(z)) ?

The integral of (sec^2(z))/(3+5tan(z)) is 1/5 ln|3+5tan(z)|+C

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integral of (sec^2(z))/(3+5tan(z))

\int \frac{sec ^{2} ( z )}{3 + 5 tan ( z )} d z

\frac{1}{5} ln ∣ 3 + 5 tan (z) ∣ + C

Solution steps

\int \frac{sec ^{2} ( z )}{3 + 5 tan ( z )} d z

Apply u-substitution

: \int \frac{1}{5 u} d u

= \int \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{5} ln ∣ u ∣

Substitute back

u = 3 + 5 tan (z)

= \frac{1}{5} ln ∣ 3 + 5 tan (z) ∣

Add a constant to the solution

= \frac{1}{5} ln ∣ 3 + 5 tan (z) ∣ + C

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What is the integral of (sec^2(z))/(3+5tan(z)) ?
The integral of (sec^2(z))/(3+5tan(z)) is 1/5 ln|3+5tan(z)|+C