What is the integral of (1/(1+y^2)) ?

The integral of (1/(1+y^2)) is arctan(y)+C

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integral of (1/(1+y^2))

\int (\frac{1}{1 + y ^{2}}) d y

arctan (y) + C

Solution steps

\int \frac{1}{1 + y ^{2}} d y

Use the common integral:

\int \frac{1}{1 + y ^{2}} d y = arctan (y)

= arctan (y)

Add a constant to the solution

= arctan (y) + C

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What is the integral of (1/(1+y^2)) ?
The integral of (1/(1+y^2)) is arctan(y)+C