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Popular >

integral of 1/(2u^2)

Solution

\int \frac{1}{2 u ^{2}} d u

Solution

- \frac{1}{2 u} + C

Solution steps

\int \frac{1}{2 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= \frac{1}{2} (- \frac{1}{u})

Simplify

\frac{1}{2} (- \frac{1}{u}) : - \frac{1}{2 u}

= - \frac{1}{2 u}

Add a constant to the solution

= - \frac{1}{2 u} + C

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\int x (1 + x) d x

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Frequently Asked Questions (FAQ)

What is the integral of 1/(2u^2) ?
The integral of 1/(2u^2) is -1/(2u)+C