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Popular >

integral of 16x^{-3}

Solution

\int 16 x^{- 3} d x

Solution

- \frac{8}{x ^{2}} + C

Solution steps

\int 16 x^{- 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int x^{- 3} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 16 (- \frac{1}{2 x ^{2}})

Simplify

16 (- \frac{1}{2 x ^{2}}) : - \frac{8}{x ^{2}}

= - \frac{8}{x ^{2}}

Add a constant to the solution

= - \frac{8}{x ^{2}} + C

Popular Examples

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\int (3 e^{x} - 5 x) d x

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\int \frac{t ^{2}}{t ^{3} - 1} d t

integral of (x^3)/((1+x))

\int \frac{x ^{3}}{( 1 + x )} d x

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\int \frac{18 x - 17}{( 2 x - 3 ) ( x + 1 )} d x

integral of (32)/(x(x^2-16))

\int \frac{32}{x ( x ^{2} - 16 )} d x

Frequently Asked Questions (FAQ)

What is the integral of 16x^{-3} ?
The integral of 16x^{-3} is -8/(x^2)+C