What is the integral of 10xe^{-x} ?

The integral of 10xe^{-x} is 10(-e^{-x}x-e^{-x})+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 10xe^{-x}

\int 10 x e^{- x} d x

10 (- e^{- x} x - e^{- x}) + C

Solution steps

\int 10 x e^{- x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int x e^{- x} d x

Apply Integration By Parts

: - e^{- x} x - \int - e^{- x} d x

= 10 (- e^{- x} x - \int - e^{- x} d x)

\int - e^{- x} d x = e^{- x}

= 10 (- e^{- x} x - e^{- x})

Add a constant to the solution

= 10 (- e^{- x} x - e^{- x}) + C

\int p (p + 5)^{6} d p

\int \frac{zy}{x} + z ln (y) d x

\int \frac{x ^{2}}{3 x ^{3} + 4} d x

\int e^{x} - (x^{2} - 1) d x

\int (1 + 4 x) d x

What is the integral of 10xe^{-x} ?
The integral of 10xe^{-x} is 10(-e^{-x}x-e^{-x})+C