What is the sum from n=0 to infinity of 1/(4^n) ?

The sum from n=0 to infinity of 1/(4^n) is 4/3

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sum from n=0 to infinity of 1/(4^n)

n = 0 \sum \infty \frac{1}{4 ^{n}}

\frac{4}{3}

Solution steps

n = 0 \sum \infty \frac{1}{4 ^{n}}

Apply Series Geometric Test:

\frac{4}{3}

= \frac{4}{3}

x \to 3 lim (f (x) (x - 1))

\frac{\partial}{\partial y} (x - y)

x \to 0 lim (\frac{( 1 1 ^{x} - 1 )}{x})

\int \frac{5}{cos ( x ) - 1} d x

What is the sum from n=0 to infinity of 1/(4^n) ?
The sum from n=0 to infinity of 1/(4^n) is 4/3