What is the integral of e^{-3x}cos(8x) ?

The integral of e^{-3x}cos(8x) is (8e^{-3x}sin(8x))/(73)-(3e^{-3x}cos(8x))/(73)+C

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integral of e^{-3x}cos(8x)

\int e^{- 3 x} cos (8 x) d x

\frac{8 e ^{- 3 x} sin ( 8 x )}{73} - \frac{3 e ^{- 3 x} cos ( 8 x )}{73} + C

Solution steps

\int e^{- 3 x} cos (8 x) d x

Apply Integration By Parts

= \frac{1}{8} e^{- 3 x} sin (8 x) - \int - \frac{3}{8} e^{- 3 x} sin (8 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} e^{- 3 x} sin (8 x) - (- \frac{3}{8} \cdot \int e^{- 3 x} sin (8 x) d x)

Apply Integration By Parts

= \frac{1}{8} e^{- 3 x} sin (8 x) - (- \frac{3}{8} (- \frac{1}{8} e^{- 3 x} cos (8 x) - \int \frac{3}{8} e^{- 3 x} cos (8 x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} e^{- 3 x} sin (8 x) - (- \frac{3}{8} (- \frac{1}{8} e^{- 3 x} cos (8 x) - \frac{3}{8} \cdot \int e^{- 3 x} cos (8 x) d x))

Therefore

\int e^{- 3 x} cos (8 x) d x = \frac{1}{8} e^{- 3 x} sin (8 x) - (- \frac{3}{8} (- \frac{1}{8} e^{- 3 x} cos (8 x) - \frac{3}{8} \cdot \int e^{- 3 x} cos (8 x) d x))

Isolate

\int e^{- 3 x} cos (8 x) d x

= \frac{8 e ^{- 3 x} sin ( 8 x )}{73} - \frac{3 e ^{- 3 x} cos ( 8 x )}{73}

Add a constant to the solution

= \frac{8 e ^{- 3 x} sin ( 8 x )}{73} - \frac{3 e ^{- 3 x} cos ( 8 x )}{73} + C

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What is the integral of e^{-3x}cos(8x) ?
The integral of e^{-3x}cos(8x) is (8e^{-3x}sin(8x))/(73)-(3e^{-3x}cos(8x))/(73)+C