What is the integral of sinh^3(4x)cosh(4x) ?

The integral of sinh^3(4x)cosh(4x) is 1/16 sinh^4(4x)+C

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integral of sinh^3(4x)cosh(4x)

\int sinh^{3} (4 x) cosh (4 x) d x

\frac{1}{16} sinh^{4} (4 x) + C

Solution steps

\int sinh^{3} (4 x) cosh (4 x) d x

Apply u-substitution

: \int sinh^{3} (u) cosh (u) \frac{1}{4} d u

= \int sinh^{3} (u) cosh (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int sinh^{3} (u) cosh (u) d u

Apply u-substitution

: \int v^{3} d v

= \frac{1}{4} \cdot \int v^{3} d v

Apply the Power Rule

: \frac{v ^{4}}{4}

= \frac{1}{4} \cdot \frac{v ^{4}}{4}

Substitute back

= \frac{1}{4} \cdot \frac{sinh ^{4} ( 4 x )}{4}

Simplify

\frac{1}{4} \cdot \frac{sinh ^{4} ( 4 x )}{4} : \frac{1}{16} sinh^{4} (4 x)

= \frac{1}{16} sinh^{4} (4 x)

Add a constant to the solution

= \frac{1}{16} sinh^{4} (4 x) + C

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What is the integral of sinh^3(4x)cosh(4x) ?
The integral of sinh^3(4x)cosh(4x) is 1/16 sinh^4(4x)+C