What is the integral of (7sqrt(x^3)+8\sqrt[3]{x^2}) ?

The integral of (7sqrt(x^3)+8\sqrt[3]{x^2}) is 14/5 x^{5/2}+24/5 x^{5/3}+C

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integral of (7sqrt(x^3)+8\sqrt[3]{x^2})

\frac{14}{5} x^{\frac{5}{2}} + \frac{24}{5} x^{\frac{5}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 7 x^{3} d x = \frac{14}{5} x^{\frac{5}{2}}

= \frac{14}{5} x^{\frac{5}{2}} + \frac{24}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{14}{5} x^{\frac{5}{2}} + \frac{24}{5} x^{\frac{5}{3}} + C

\int \frac{3 x}{( 1 + 9 x ^{2} ) ^{4}} d x

sin^{2} (t)

\int 8 x^{7} e^{8 x^{8}} d x

What is the integral of (7sqrt(x^3)+8\sqrt[3]{x^2}) ?
The integral of (7sqrt(x^3)+8\sqrt[3]{x^2}) is 14/5 x^{5/2}+24/5 x^{5/3}+C