What is the integral of 1/(4\sqrt[3]{x^4)} ?

The integral of 1/(4\sqrt[3]{x^4)} is -3/(4\sqrt[3]{x)}+C

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integral of 1/(4\sqrt[3]{x^4)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{1}{4} \cdot \int \frac{1}{x ^{\frac{4}{3}}} d x

Apply the Power Rule

Simplify

Add a constant to the solution

\int \frac{1}{2 v} d v

\int \frac{x}{2 x + 1} d x

\int (2 x^{2} + 4)^{8} \cdot x d x

\int \frac{sin ( 3 x )}{e ^{x}} d x

\int \frac{cos ( x )}{sin ( x ) ( 1 + sin ( x ) )} d x

What is the integral of 1/(4\sqrt[3]{x^4)} ?
The integral of 1/(4\sqrt[3]{x^4)} is -3/(4\sqrt[3]{x)}+C