What is the integral of ((x^2)/2+x) ?

The integral of ((x^2)/2+x) is (x^3)/6+(x^2)/2+C

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integral of ((x^2)/2+x)

\int (\frac{x ^{2}}{2} + x) d x

\frac{x ^{3}}{6} + \frac{x ^{2}}{2} + C

Solution steps

\int \frac{x ^{2}}{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x ^{2}}{2} d x + \int x d x

\int \frac{x ^{2}}{2} d x = \frac{x ^{3}}{6}

\int x d x = \frac{x ^{2}}{2}

= \frac{x ^{3}}{6} + \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{3}}{6} + \frac{x ^{2}}{2} + C

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What is the integral of ((x^2)/2+x) ?
The integral of ((x^2)/2+x) is (x^3)/6+(x^2)/2+C