What is the integral of ((x^2))/(sqrt(x^3+5)) ?

The integral of ((x^2))/(sqrt(x^3+5)) is 2/3 sqrt(x^3+5)+C

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integral of ((x^2))/(sqrt(x^3+5))

\int \frac{( x ^{2} )}{x ^{3} + 5} d x

\frac{2}{3} x^{3} + 5 + C

Solution steps

\int \frac{x ^{2}}{x ^{3} + 5} d x

Apply u-substitution

: \int \frac{2}{3} d u

= \int \frac{2}{3} d u

Integral of a constant:

\int a d x = a x

= \frac{2}{3} u

Substitute back

u = x^{3} + 5

= \frac{2}{3} x^{3} + 5

Add a constant to the solution

= \frac{2}{3} x^{3} + 5 + C

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What is the integral of ((x^2))/(sqrt(x^3+5)) ?
The integral of ((x^2))/(sqrt(x^3+5)) is 2/3 sqrt(x^3+5)+C