What is the integral of 3x^2+2x-5 ?

The integral of 3x^2+2x-5 is x^3+x^2-5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3x^2+2x-5

\int 3 x^{2} + 2 x - 5 d x

x^{3} + x^{2} - 5 x + C

Solution steps

\int 3 x^{2} + 2 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int 2 x d x - \int 5 d x

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

\int 5 d x = 5 x

= x^{3} + x^{2} - 5 x

Add a constant to the solution

= x^{3} + x^{2} - 5 x + C

\int 5 cot^{5} (x) d x

\int (\frac{1}{x ^{3}} + x^{2}) d x

\int \frac{( t ^{6} )}{1 - t ^{14}} d t

\int sin (4 x - 5) d x

\int (2 x + 3) 2 x - 1 d x