What is the integral of (e^x)/(e^{x+1)} ?

The integral of (e^x)/(e^{x+1)} is 1/e x+C

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integral of (e^x)/(e^{x+1)}

\int \frac{e ^{x}}{e ^{x + 1}} d x

\frac{1}{e} x + C

Solution steps

\int \frac{e ^{x}}{e ^{x + 1}} d x

\frac{e ^{x}}{e ^{x + 1}} = \frac{1}{e}

= \int \frac{1}{e} d x

Integral of a constant:

\int a d x = a x

= \frac{1}{e} x

Add a constant to the solution

= \frac{1}{e} x + C

\int \frac{1 + 2 x}{1 + x} d x

\int \frac{sin ( a ) x}{cos ( a ) x + b} d x

\int e^{x} (e^{x} + 1) d x

\int 2 + 3 x d x

\int 2 x^{2} + 3 x d x

What is the integral of (e^x)/(e^{x+1)} ?
The integral of (e^x)/(e^{x+1)} is 1/e x+C