What is the integral of e^{20}sin(3θ) ?

The integral of e^{20}sin(3θ) is -(e^{20})/3 cos(3θ)+C

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integral of e^{20}sin(3θ)

\int e^{20} sin (3 θ) d θ

- \frac{e ^{20}}{3} cos (3 θ) + C

Solution steps

\int e^{20} sin (3 θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{20} \cdot \int sin (3 θ) d θ

Apply u-substitution

: \int sin (u) \frac{1}{3} d u

= e^{20} \cdot \int sin (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{20} \frac{1}{3} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= e^{20} \frac{1}{3} (- cos (u))

Substitute back

u = 3 θ

= e^{20} \frac{1}{3} (- cos (3 θ))

Simplify

e^{20} \frac{1}{3} (- cos (3 θ)) : - \frac{e ^{20}}{3} cos (3 θ)

= - \frac{e ^{20}}{3} cos (3 θ)

Add a constant to the solution

= - \frac{e ^{20}}{3} cos (3 θ) + C

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What is the integral of e^{20}sin(3θ) ?
The integral of e^{20}sin(3θ) is -(e^{20})/3 cos(3θ)+C