What is the integral of x/((x^2+5)) ?

The integral of x/((x^2+5)) is 1/2 ln|x^2+5|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x/((x^2+5))

\int \frac{x}{( x ^{2} + 5 )} d x

\frac{1}{2} ln x^{2} + 5 + C

Solution steps

\int \frac{x}{x ^{2} + 5} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = x^{2} + 5

= \frac{1}{2} ln x^{2} + 5

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 5 + C

\int \frac{1}{x ^{2} \cdot x ^{2} - 16} d x

\int \frac{tan ( 5 x )}{cos ^{2} ( 5 x )} d x

\int e^{3 x} \cdot cos (2 x) d x

\int x \cdot arctan (\frac{1}{x}) d x

\int x (2 x + 5)^{12} d x

What is the integral of x/((x^2+5)) ?
The integral of x/((x^2+5)) is 1/2 ln|x^2+5|+C