What is the integral of 5sec(4x)tan(4x) ?

The integral of 5sec(4x)tan(4x) is 5/4 sec(4x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 5sec(4x)tan(4x)

\int 5 sec (4 x) tan (4 x) d x

\frac{5}{4} sec (4 x) + C

Solution steps

\int 5 sec (4 x) tan (4 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int sec (4 x) tan (4 x) d x

Apply u-substitution

: \int \frac{1}{4} d u

= 5 \cdot \int \frac{1}{4} d u

Integral of a constant:

\int a d x = a x

= 5 \cdot \frac{1}{4} u

Substitute back

u = sec (4 x)

= 5 \cdot \frac{1}{4} sec (4 x)

Simplify

5 \cdot \frac{1}{4} sec (4 x) : \frac{5}{4} sec (4 x)

= \frac{5}{4} sec (4 x)

Add a constant to the solution

= \frac{5}{4} sec (4 x) + C

\int (2 x - 5) sin (x) d x

\int \frac{1}{x ^{5} + x ^{4}} d x

\int \frac{( 8 \cdot x + 5 )}{( x ^{2} + 1 )} d x

\int csc^{4} (5 x) d x

\int 1 - x x^{2} d x

What is the integral of 5sec(4x)tan(4x) ?
The integral of 5sec(4x)tan(4x) is 5/4 sec(4x)+C