What is the integral of t^2-2t-24 ?

The integral of t^2-2t-24 is (t^3)/3-t^2-24t+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of t^2-2t-24

\int t^{2} - 2 t - 24 d t

\frac{t ^{3}}{3} - t^{2} - 24 t + C

Solution steps

\int t^{2} - 2 t - 24 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int t^{2} d t - \int 2 t d t - \int 24 d t

\int t^{2} d t = \frac{t ^{3}}{3}

\int 2 t d t = t^{2}

\int 24 d t = 24 t

= \frac{t ^{3}}{3} - t^{2} - 24 t

Add a constant to the solution

= \frac{t ^{3}}{3} - t^{2} - 24 t + C

\int \frac{2 x ^{3} + 7 x}{x ^{4} + 7 x ^{2} + 3} d x

\int t^{2} cos^{2} (t^{3}) sin (t^{3}) d t

\int \frac{1}{cos ^{2} ( 3 u )} d u

\int 8 x + sin (x) d x

\int \frac{sec ( x )}{tan ^{4} ( x )} d x

What is the integral of t^2-2t-24 ?
The integral of t^2-2t-24 is (t^3)/3-t^2-24t+C