What is the integral of x^3-3x^2+2 ?

The integral of x^3-3x^2+2 is (x^4)/4-x^3+2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^3-3x^2+2

\int x^{3} - 3 x^{2} + 2 d x

\frac{x ^{4}}{4} - x^{3} + 2 x + C

Solution steps

\int x^{3} - 3 x^{2} + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 3 x^{2} d x + \int 2 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 3 x^{2} d x = x^{3}

\int 2 d x = 2 x

= \frac{x ^{4}}{4} - x^{3} + 2 x

Add a constant to the solution

= \frac{x ^{4}}{4} - x^{3} + 2 x + C

\int 4 arctan (4 x) d x

y

\int (x^{3} + 1)^{6} 3 x^{2} d x

\int tan^{2} (x) sin^{2} (x) d x

\int x sin (12 x) d x

What is the integral of x^3-3x^2+2 ?
The integral of x^3-3x^2+2 is (x^4)/4-x^3+2x+C