What is the integral of (12x^2+6x-5) ?

The integral of (12x^2+6x-5) is 4x^3+3x^2-5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (12x^2+6x-5)

\int (12 x^{2} + 6 x - 5) d x

4 x^{3} + 3 x^{2} - 5 x + C

Solution steps

\int 12 x^{2} + 6 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{2} d x + \int 6 x d x - \int 5 d x

\int 12 x^{2} d x = 4 x^{3}

\int 6 x d x = 3 x^{2}

\int 5 d x = 5 x

= 4 x^{3} + 3 x^{2} - 5 x

Add a constant to the solution

= 4 x^{3} + 3 x^{2} - 5 x + C

\int \frac{5 x - 3}{x ^{2} + 7 x + 6} d x

\int \frac{3}{144 + 49 x ^{2}} d x

\int \frac{1}{3 e ^{x}} d x

\int - 2 x^{2} + 2 x d x

\int \frac{x ^{2} + x ^{- 2} + 2}{x} d x

What is the integral of (12x^2+6x-5) ?
The integral of (12x^2+6x-5) is 4x^3+3x^2-5x+C