What is the solution for derivative of x^2+y^2=25 ?

The solution for derivative of x^2+y^2=25 is y=sqrt(25x+c_{1)-x^2},y=-sqrt(25x+c_{1)-x^2}

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derivative of x^2+y^2=25

\frac{d}{d x} (x^{2} + y^{2}) = 25

y = 25 x + c_{1} - x^{2}, y = - 25 x + c_{1} - x^{2}

Solution steps

\frac{d}{d x} (x^{2} + y^{2}) = 25

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

x^{2} + y^{2} = \int 25 d x

\int 25 d x = 25 x + c_{1}

x^{2} + y^{2} = 25 x + c_{1}

Isolate

y : y = 25 x + c_{1} - x^{2}, y = - 25 x + c_{1} - x^{2}

y = 25 x + c_{1} - x^{2}, y = - 25 x + c_{1} - x^{2}

\frac{\partial}{\partial x} (9 x^{2})

f (x) = 4 - x^{2}

x \to - 2 lim (\frac{x ^{2} - 1}{2 - x})

y = x, (25, 5)

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 1}{x ^{2} + 1})

What is the solution for derivative of x^2+y^2=25 ?
The solution for derivative of x^2+y^2=25 is y=sqrt(25x+c_{1)-x^2},y=-sqrt(25x+c_{1)-x^2}