What is the integral of sec^2(x)-tan^2(x) ?

The integral of sec^2(x)-tan^2(x) is x+C

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integral of sec^2(x)-tan^2(x)

\int sec^{2} (x) - tan^{2} (x) d x

x + C

Solution steps

\int sec^{2} (x) - tan^{2} (x) d x

Rewrite using trig identities

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

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What is the integral of sec^2(x)-tan^2(x) ?
The integral of sec^2(x)-tan^2(x) is x+C