What is the integral of e^{-0.0025x} ?

The integral of e^{-0.0025x} is -400e^{-0.0025x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{-0.0025x}

\int e^{- 0.0025 x} d x

- 400 e^{- 0.0025 x} + C

Solution steps

\int e^{- 0.0025 x} d x

Apply u-substitution

: \int - \frac{1}{0.0025} e^{u} d u

= \int - \frac{1}{0.0025} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{0.0025} \cdot \int e^{u} d u

Simplify

= - 400 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 400 e^{u}

Substitute back

u = - 0.0025 x

= - 400 e^{- 0.0025 x}

Add a constant to the solution

= - 400 e^{- 0.0025 x} + C

\int x^{2} - 2 x + 3 d x

\int \frac{( 2 x - 3 )}{x ^{2} + 6 x + 13} d x

\int \frac{x + 3}{( x ^{2} + 2 x + 5 ) ^{2}} d x

\int \frac{t ^{3}}{t ^{2} - 9} d t

\int d arctan (x) d x

What is the integral of e^{-0.0025x} ?
The integral of e^{-0.0025x} is -400e^{-0.0025x}+C