What is the integral of 1/((sin(2x))^2) ?

The integral of 1/((sin(2x))^2) is -1/2 cot(2x)+C

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integral of 1/((sin(2x))^2)

\int \frac{1}{( sin ( 2 x ) ) ^{2}} d x

- \frac{1}{2} cot (2 x) + C

Solution steps

\int \frac{1}{( sin ( 2 x ) ) ^{2}} d x

Rewrite using trig identities

= \int csc^{2} (2 x) d x

Apply u-substitution

: \int csc^{2} (u) \frac{1}{2} d u

= \int csc^{2} (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int csc^{2} (u) d u

Use the common integral:

\int csc^{2} (u) d u = - cot (u)

= \frac{1}{2} (- cot (u))

Substitute back

u = 2 x

= \frac{1}{2} (- cot (2 x))

Simplify

= - \frac{1}{2} cot (2 x)

Add a constant to the solution

= - \frac{1}{2} cot (2 x) + C

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What is the integral of 1/((sin(2x))^2) ?
The integral of 1/((sin(2x))^2) is -1/2 cot(2x)+C