What is the integral of 1/(sqrt(2h)) ?

The integral of 1/(sqrt(2h)) is sqrt(h/2)+1/(sqrt(2))sqrt(h)+C

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integral of 1/(sqrt(2h))

\int \frac{1}{2 h} d h

\frac{h}{2} + \frac{1}{2} h + C

Solution steps

\int \frac{1}{2 h} d h

Apply Integration By Parts

= \frac{h}{2} - \int - \frac{1}{2 2 h ^{\frac{1}{2}}} d h

\int - \frac{1}{2 2 h ^{\frac{1}{2}}} d h = - \frac{1}{2} h

= \frac{h}{2} - (- \frac{1}{2} h)

Simplify

= \frac{h}{2} + \frac{1}{2} h

Add a constant to the solution

= \frac{h}{2} + \frac{1}{2} h + C

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What is the integral of 1/(sqrt(2h)) ?
The integral of 1/(sqrt(2h)) is sqrt(h/2)+1/(sqrt(2))sqrt(h)+C