What is the integral of sec(x)sec(x)+tan(x) ?

The integral of sec(x)sec(x)+tan(x) is tan(x)-ln|cos(x)|+C

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integral of sec(x)sec(x)+tan(x)

\int sec (x) sec (x) + tan (x) d x

tan (x) - ln ∣ cos (x) ∣ + C

Solution steps

\int sec (x) sec (x) + tan (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec (x) sec (x) d x + \int tan (x) d x

\int sec (x) sec (x) d x = tan (x)

\int tan (x) d x = - ln ∣ cos (x) ∣

= tan (x) - ln ∣ cos (x) ∣

Add a constant to the solution

= tan (x) - ln ∣ cos (x) ∣ + C

\int \frac{2 ^{x + 1} - 5 ^{x + 1}}{1 0 ^{x}} d x

\int θ^{2} + 1 d θ

\int 3 x^{2} - 2 x + 7 e^{x} d x

\int (x + 2) (x - 5)^{4} d x

What is the integral of sec(x)sec(x)+tan(x) ?
The integral of sec(x)sec(x)+tan(x) is tan(x)-ln|cos(x)|+C