What is the integral of (e^y)/2 ?

The integral of (e^y)/2 is 1/2 e^y+C

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integral of (e^y)/2

\int \frac{e ^{y}}{2} d y

\frac{1}{2} e^{y} + C

Solution steps

\int \frac{e ^{y}}{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{y} d y

Use the common integral:

\int e^{y} d y = e^{y}

= \frac{1}{2} e^{y}

Add a constant to the solution

= \frac{1}{2} e^{y} + C

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