What is the integral of (x^2-3sqrt(x))/(\sqrt[3]{x)} ?

The integral of (x^2-3sqrt(x))/(\sqrt[3]{x)} is 3/8 x^{8/3}-18/7 x^{7/6}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2-3sqrt(x))/(\sqrt[3]{x)}

\frac{3}{8} x^{\frac{8}{3}} - \frac{18}{7} x^{\frac{7}{6}} + C

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x^{\frac{5}{3}} d x = \frac{3}{8} x^{\frac{8}{3}}

= \frac{3}{8} x^{\frac{8}{3}} - \frac{18}{7} x^{\frac{7}{6}}

Add a constant to the solution

= \frac{3}{8} x^{\frac{8}{3}} - \frac{18}{7} x^{\frac{7}{6}} + C

\int \frac{2 x ^{4} + 3 x ^{2} + 4}{x ^{2} + 1} d x

\int \frac{10 sec ^{2} ( 3 x )}{tan ( 3 x ) - 3} d x

\int \frac{9 x ^{2} - 3 x + 1}{x ^{3} - x ^{2}} d x

\int 3^{c o s (x)} sin (x) d x

\int x^{2} + 1 x d x

What is the integral of (x^2-3sqrt(x))/(\sqrt[3]{x)} ?
The integral of (x^2-3sqrt(x))/(\sqrt[3]{x)} is 3/8 x^{8/3}-18/7 x^{7/6}+C