What is the integral of 2\sqrt[3]{x^2} ?

The integral of 2\sqrt[3]{x^2} is 6/5 x^{5/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2\sqrt[3]{x^2}

\frac{6}{5} x^{\frac{5}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 2 \cdot \int x^{\frac{2}{3}} d x

Apply the Power Rule

: \frac{3}{5} x^{\frac{5}{3}}

= 2 \cdot \frac{3}{5} x^{\frac{5}{3}}

Simplify

2 \cdot \frac{3}{5} x^{\frac{5}{3}} : \frac{6}{5} x^{\frac{5}{3}}

= \frac{6}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{6}{5} x^{\frac{5}{3}} + C

\int (\frac{6}{5 + 5 x ^{2}}) d x

\int 2 t + 9 d t

\int \frac{2 x + 1}{( 2 x ^{2} + 2 x ) ^{2}} d x

\int \frac{( ln ( x ) )}{x ^{4}} d x

\int \frac{x ^{2}}{4 + x ^{3}} d x

What is the integral of 2\sqrt[3]{x^2} ?
The integral of 2\sqrt[3]{x^2} is 6/5 x^{5/3}+C