What is the derivative of (12/x-4/(x^3)+1/(x^4)) ?

The derivative of (12/x-4/(x^3)+1/(x^4)) is -(12)/(x^2)+(12)/(x^4)-4/(x^5)

What is the first derivative of (12/x-4/(x^3)+1/(x^4)) ?

The first derivative of (12/x-4/(x^3)+1/(x^4)) is -(12)/(x^2)+(12)/(x^4)-4/(x^5)

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\frac{d}{d x} (\frac{12}{x} - \frac{4}{x ^{3}} + \frac{1}{x ^{4}})

- \frac{12}{x ^{2}} + \frac{12}{x ^{4}} - \frac{4}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{12}{x} - \frac{4}{x ^{3}} + \frac{1}{x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{12}{x}) - \frac{d}{d x} (\frac{4}{x ^{3}}) + \frac{d}{d x} (\frac{1}{x ^{4}})

\frac{d}{d x} (\frac{12}{x}) = - \frac{12}{x ^{2}}

\frac{d}{d x} (\frac{4}{x ^{3}}) = - \frac{12}{x ^{4}}

\frac{d}{d x} (\frac{1}{x ^{4}}) = - \frac{4}{x ^{5}}

= - \frac{12}{x ^{2}} - (- \frac{12}{x ^{4}}) - \frac{4}{x ^{5}}

Simplify

= - \frac{12}{x ^{2}} + \frac{12}{x ^{4}} - \frac{4}{x ^{5}}

y^{^{''}} + 2 y^{^{'}} + y = 0, y (2) = 1, y^{^{'}} (2) = - 2

\int \frac{( x ^{2} - x + 1 )}{( x ^{2} + x )} d x

\frac{d}{d x} (11 x - \frac{6}{x})

\int t^{6} e^{- t^{7}} d t

\int \frac{1}{v ^{2} - 1} d v

What is the derivative of (12/x-4/(x^3)+1/(x^4)) ?
The derivative of (12/x-4/(x^3)+1/(x^4)) is -(12)/(x^2)+(12)/(x^4)-4/(x^5)
What is the first derivative of (12/x-4/(x^3)+1/(x^4)) ?
The first derivative of (12/x-4/(x^3)+1/(x^4)) is -(12)/(x^2)+(12)/(x^4)-4/(x^5)