What is the integral of e^x+12x^2-4 ?

The integral of e^x+12x^2-4 is e^x+4x^3-4x+C

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integral of e^x+12x^2-4

\int e^{x} + 12 x^{2} - 4 d x

e^{x} + 4 x^{3} - 4 x + C

Solution steps

\int e^{x} + 12 x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x + \int 12 x^{2} d x - \int 4 d x

\int e^{x} d x = e^{x}

\int 12 x^{2} d x = 4 x^{3}

\int 4 d x = 4 x

= e^{x} + 4 x^{3} - 4 x

Add a constant to the solution

= e^{x} + 4 x^{3} - 4 x + C

\int \frac{1}{( 4 x ^{2} - 24 x + 27 ) ^{3}} d x

\int 3 x^{2} (x^{3} - 5)^{4} d x

\int 4 x^{2} - 5 x d x

\int \frac{1}{( x ( x ^{2} + 1 ) )} d x

\int (x^{2} + 2)^{5} 2 x d x

What is the integral of e^x+12x^2-4 ?
The integral of e^x+12x^2-4 is e^x+4x^3-4x+C