What is the tangent of f(x)= 2/x ,(6, 1/3) ?

The tangent of f(x)= 2/x ,(6, 1/3) is y=-1/18 x+2/3

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tangent of f(x)= 2/x ,(6, 1/3)

tangent of

f (x) = \frac{2}{x}, (6, \frac{1}{3})

y = - \frac{1}{18} x + \frac{2}{3}

Solution steps

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

(6, \frac{1}{3}) : m = - \frac{1}{18}

Find the line with slope m=

- \frac{1}{18}

and passing through

(6, \frac{1}{3}) : y = - \frac{1}{18} x + \frac{2}{3}

y = - \frac{1}{18} x + \frac{2}{3}

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What is the tangent of f(x)= 2/x ,(6, 1/3) ?
The tangent of f(x)= 2/x ,(6, 1/3) is y=-1/18 x+2/3