What is the integral of 4cos(1/4 pix) ?

The integral of 4cos(1/4 pix) is (16)/pi sin((pix)/4)+C

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integral of 4cos(1/4 pix)

\int 4 cos (\frac{1}{4} π x) d x

\frac{16}{π} sin (\frac{π x}{4}) + C

Solution steps

\int 4 cos (\frac{1}{4} π x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int cos (\frac{1}{4} π x) d x

Simplify

\frac{1}{4} π x : \frac{π x}{4}

= 4 \cdot \int cos (\frac{π x}{4}) d x

Apply u-substitution

= 4 \cdot \int cos (u) \frac{4}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{4}{π} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 4 \cdot \frac{4}{π} sin (u)

Substitute back

u = \frac{π x}{4}

= 4 \cdot \frac{4}{π} sin (\frac{π x}{4})

Simplify

4 \cdot \frac{4}{π} sin (\frac{π x}{4}) : \frac{16}{π} sin (\frac{π x}{4})

= \frac{16}{π} sin (\frac{π x}{4})

Add a constant to the solution

= \frac{16}{π} sin (\frac{π x}{4}) + C

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What is the integral of 4cos(1/4 pix) ?
The integral of 4cos(1/4 pix) is (16)/pi sin((pix)/4)+C