What is the integral of (6+x^2)/(sqrt(x)) ?

The integral of (6+x^2)/(sqrt(x)) is 12sqrt(x)+2/5 x^{5/2}+C

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integral of (6+x^2)/(sqrt(x))

\int \frac{6 + x ^{2}}{x} d x

12 x + \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int \frac{6 + x ^{2}}{x} d x

Expand

\frac{6 + x ^{2}}{x} : \frac{6}{x} + x^{\frac{3}{2}}

= \int \frac{6}{x} + x^{\frac{3}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{x} d x + \int x^{\frac{3}{2}} d x

\int \frac{6}{x} d x = 12 x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

= 12 x + \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= 12 x + \frac{2}{5} x^{\frac{5}{2}} + C

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What is the integral of (6+x^2)/(sqrt(x)) ?
The integral of (6+x^2)/(sqrt(x)) is 12sqrt(x)+2/5 x^{5/2}+C