What is the integral of 4sqrt(y) ?

The integral of 4sqrt(y) is 8/3 y^{3/2}+C

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integral of 4sqrt(y)

\int 4 y d y

\frac{8}{3} y^{\frac{3}{2}} + C

Solution steps

\int 4 y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int y d y

Apply the Power Rule

: \frac{2}{3} y^{\frac{3}{2}}

= 4 \cdot \frac{2}{3} y^{\frac{3}{2}}

Simplify

4 \cdot \frac{2}{3} y^{\frac{3}{2}} : \frac{8}{3} y^{\frac{3}{2}}

= \frac{8}{3} y^{\frac{3}{2}}

Add a constant to the solution

= \frac{8}{3} y^{\frac{3}{2}} + C

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