What is the integral of ln^2(x) ?

The integral of ln^2(x) is xln^2(x)-2(xln(x)-x)+C

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integral of ln^2(x)

integral

ln^{2} (x)

x ln^{2} (x) - 2 (x ln (x) - x) + C

Solution steps

\int ln^{2} (x) d x

Apply Integration By Parts

: x ln^{2} (x) - \int 2 ln (x) d x

= x ln^{2} (x) - \int 2 ln (x) d x

\int 2 ln (x) d x = 2 (x ln (x) - x)

= x ln^{2} (x) - 2 (x ln (x) - x)

Add a constant to the solution

= x ln^{2} (x) - 2 (x ln (x) - x) + C

\int 1 ln (x) d x

\int (x^{3} + 5 x^{2} - 2) d x

\int (x^{3} + 1) d x

\int \frac{( x ^{2} + x + 6 )}{x ^{3} + 4 x ^{2} + 6 x} d x

\int 2 x \cdot 1 + x^{2} d x

What is the integral of ln^2(x) ?
The integral of ln^2(x) is xln^2(x)-2(xln(x)-x)+C