What is the integral of (e^{5x})/(e^{5x)+4} ?

The integral of (e^{5x})/(e^{5x)+4} is 1/5 ln|e^{5x}+4|+C

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integral of (e^{5x})/(e^{5x)+4}

\int \frac{e ^{5 x}}{e ^{5 x} + 4} d x

\frac{1}{5} ln e^{5 x} + 4 + C

Solution steps

\int \frac{e ^{5 x}}{e ^{5 x} + 4} d x

Apply u-substitution

: \int \frac{1}{5 u} d u

= \int \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{5} ln ∣ u ∣

Substitute back

u = e^{5 x} + 4

= \frac{1}{5} ln e^{5 x} + 4

Add a constant to the solution

= \frac{1}{5} ln e^{5 x} + 4 + C

\frac{\partial}{\partial y} (π x^{2} y)

\int 21 x^{2} ln (x) d x

\frac{d y}{d t} = t e^{2 y}

\int x ln (3 x^{2}) d x

\frac{1}{x} d x + d y = 0

What is the integral of (e^{5x})/(e^{5x)+4} ?
The integral of (e^{5x})/(e^{5x)+4} is 1/5 ln|e^{5x}+4|+C