What is the integral of 1/(\sqrt[3]{x^5)}+sin(x) ?

The integral of 1/(\sqrt[3]{x^5)}+sin(x) is -3/(2x^{2/3)}-cos(x)+C

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integral of 1/(\sqrt[3]{x^5)}+sin(x)

- \frac{3}{2 x ^{\frac{2}{3}}} - cos (x) + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int sin (x) d x = - cos (x)

= - \frac{3}{2 x ^{\frac{2}{3}}} - cos (x)

Add a constant to the solution

= - \frac{3}{2 x ^{\frac{2}{3}}} - cos (x) + C

\int \frac{3}{- 5 x + 2} d x

\int \frac{1 + tan ( x )}{sec ( x )} d x

\int p (p + 1)^{8} d p

\int x^{\frac{7}{4}} d x

What is the integral of 1/(\sqrt[3]{x^5)}+sin(x) ?
The integral of 1/(\sqrt[3]{x^5)}+sin(x) is -3/(2x^{2/3)}-cos(x)+C