What is the integral of (x^{1/2})/x ?

The integral of (x^{1/2})/x is 2x^{1/2}+C

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integral of (x^{1/2})/x

\int \frac{x ^{\frac{1}{2}}}{x} d x

2 x^{\frac{1}{2}} + C

Solution steps

\int \frac{x ^{\frac{1}{2}}}{x} d x

Simplify

\frac{x ^{\frac{1}{2}}}{x} : \frac{1}{x ^{\frac{1}{2}}}

= \int \frac{1}{x ^{\frac{1}{2}}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Add a constant to the solution

= 2 x^{\frac{1}{2}} + C

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