What is the integral of 5x^4-4/(x^4) ?

The integral of 5x^4-4/(x^4) is x^5+4/(3x^3)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 5x^4-4/(x^4)

\int 5 x^{4} - \frac{4}{x ^{4}} d x

x^{5} + \frac{4}{3 x ^{3}} + C

Solution steps

\int 5 x^{4} - \frac{4}{x ^{4}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x - \int \frac{4}{x ^{4}} d x

\int 5 x^{4} d x = x^{5}

\int \frac{4}{x ^{4}} d x = - \frac{4}{3 x ^{3}}

= x^{5} - (- \frac{4}{3 x ^{3}})

Simplify

= x^{5} + \frac{4}{3 x ^{3}}

Add a constant to the solution

= x^{5} + \frac{4}{3 x ^{3}} + C

\int \frac{( 1 + x )}{1 - x} d x

\int x^{5} ln (2 x^{3}) d x

\int \frac{x ^{3} - 2 x ^{2} + x - 1}{x ^{2} - 1} d x

What is the integral of 5x^4-4/(x^4) ?
The integral of 5x^4-4/(x^4) is x^5+4/(3x^3)+C