What is the integral of cos(mx)cos(nx) ?

The integral of cos(mx)cos(nx) is 1/2 (1/(m+n)sin(mx+nx)+1/(m-n)sin(mx-nx))+C

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integral of cos(mx)cos(nx)

\int cos (m x) cos (n x) d x

\frac{1}{2} (\frac{1}{m + n} sin (m x + n x) + \frac{1}{m - n} sin (m x - n x)) + C

Solution steps

\int cos (m x) cos (n x) d x

Rewrite using trig identities

= \int \frac{cos ( m x + n x ) + cos ( m x - n x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int cos (m x + n x) + cos (m x - n x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int cos (m x + n x) d x + \int cos (m x - n x) d x)

\int cos (m x + n x) d x = \frac{1}{m + n} sin (m x + n x)

\int cos (m x - n x) d x = \frac{1}{m - n} sin (m x - n x)

= \frac{1}{2} (\frac{1}{m + n} sin (m x + n x) + \frac{1}{m - n} sin (m x - n x))

Add a constant to the solution

= \frac{1}{2} (\frac{1}{m + n} sin (m x + n x) + \frac{1}{m - n} sin (m x - n x)) + C

\int \frac{1}{( x + 1 ) ( x ^{2} + 2 ) ^{2}} d x

\int \frac{x}{( 25 - x ^{2} ) ^{\frac{3}{2}}} d x

- \frac{1}{x}

\int \frac{x + ln ( x )}{x} d x

\int \frac{csc ( x ) cos ( x )}{sin ( x )} d x

What is the integral of cos(mx)cos(nx) ?
The integral of cos(mx)cos(nx) is 1/2 (1/(m+n)sin(mx+nx)+1/(m-n)sin(mx-nx))+C