What is the integral of e^{u+1} ?

The integral of e^{u+1} is e^{1+u}+C

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integral of e^{u+1}

\int e^{u + 1} d u

e^{1 + u} + C

Solution steps

\int e^{u + 1} d u

e^{u + 1} = e^{1} e^{u}

= \int e^{1} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{1} \cdot \int e^{u} d u

Simplify

= e \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e e^{u}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e e^{u} = e^{1 + u}

= e^{1 + u}

Add a constant to the solution

= e^{1 + u} + C

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