What is the integral of (x^3+x^2-x+2)/(sqrt(x)) ?

The integral of (x^3+x^2-x+2)/(sqrt(x)) is 2/7 x^{7/2}+2/5 x^{5/2}-2/3 x^{3/2}+4sqrt(x)+C

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integral of (x^3+x^2-x+2)/(sqrt(x))

\int \frac{x ^{3} + x ^{2} - x + 2}{x} d x

\frac{2}{7} x^{\frac{7}{2}} + \frac{2}{5} x^{\frac{5}{2}} - \frac{2}{3} x^{\frac{3}{2}} + 4 x + C

Solution steps

\int \frac{x ^{3} + x ^{2} - x + 2}{x} d x

Expand

\frac{x ^{3} + x ^{2} - x + 2}{x} : x^{\frac{5}{2}} + x^{\frac{3}{2}} - x + \frac{2}{x}

= \int x^{\frac{5}{2}} + x^{\frac{3}{2}} - x + \frac{2}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{5}{2}} d x + \int x^{\frac{3}{2}} d x - \int x d x + \int \frac{2}{x} d x

\int x^{\frac{5}{2}} d x = \frac{2}{7} x^{\frac{7}{2}}

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int \frac{2}{x} d x = 4 x

= \frac{2}{7} x^{\frac{7}{2}} + \frac{2}{5} x^{\frac{5}{2}} - \frac{2}{3} x^{\frac{3}{2}} + 4 x

Add a constant to the solution

= \frac{2}{7} x^{\frac{7}{2}} + \frac{2}{5} x^{\frac{5}{2}} - \frac{2}{3} x^{\frac{3}{2}} + 4 x + C

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What is the integral of (x^3+x^2-x+2)/(sqrt(x)) ?
The integral of (x^3+x^2-x+2)/(sqrt(x)) is 2/7 x^{7/2}+2/5 x^{5/2}-2/3 x^{3/2}+4sqrt(x)+C