What is the limit as x approaches infinity+of 1/(sqrt(x^2+x)) ?

The limit as x approaches infinity+of 1/(sqrt(x^2+x)) is 0

Popular >

limit as x approaches infinity+of 1/(sqrt(x^2+x))

x \to \infty + lim (\frac{1}{x ^{2} + x})

0

Solution steps

x \to \infty lim (\frac{1}{x ^{2} + x})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to \infty} ( 1 )}{lim _{x \to \infty} ( x ^{2} + x )}

x \to \infty lim (1) = 1

x \to \infty lim (x^{2} + x) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

\int 1 + (3 x^{\frac{1}{2}})^{2} d x

\int_{\frac{1}{5}}^{7} 16 x ln (5 x) d x

\int_{2}^{4} (x^{2} + 4)^{3} x d x

\frac{d}{d x} (\frac{ln ( 3 x + 1 )}{6 x + 2})

\frac{9}{sin ( x ) + cos ( x )}

What is the limit as x approaches infinity+of 1/(sqrt(x^2+x)) ?
The limit as x approaches infinity+of 1/(sqrt(x^2+x)) is 0